126a=49a^2+81

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Solution for 126a=49a^2+81 equation: 



126a=49a^2+81

We move all terms to the left:

126a-(49a^2+81)=0

We get rid of parentheses

-49a^2+126a-81=0

a = -49; b = 126; c = -81;
Δ = b2-4ac
Δ = 1262-4·(-49)·(-81)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{-126}{-98}=1+2/7$

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